So the problem goes like this:
How many ways can a hand of five cards consisting of four cards from one suit and one card from another suit be drawn from a standard deck of cards?
So I was all like:
nCr(4, 13) * nCr(1, 13) because you can choose 4 from one suit of cards (which is 13 cards in total) and then 1 from the other...
I get 9295 but the book is like no: the answer is not 9295...
It is instead 111,540... So I'm all like ok:
Lets try nCr(4, 13) * nCr(1,39) basically saying it is every other suite (52-13), but that did not give the right answer.
And now I'm all stuck on this problem. Can you help me? Thanks in advanced.