# Card Game With Replacement

• May 10th 2011, 10:03 AM
jillby
Card Game With Replacement
I'm studying for an EOCT and there is a question on the study guide this one has me stumped. I "get" how to figure general probability questions, but I can't wrap my head around this one due to the number of variables. If you could provide the formula you use and any explanation you are willing to share I would be so, so appreciative.

IN a game a player draws and replaces a card form a deck 2 times. The possible outcomes and payouts are shown. If Jim plays the game 50 times what is his expected value for all the games combined?

Red, Red \$12
Black, Black -\$5
Red, Black \$0
Black, Red \$5
• May 10th 2011, 10:08 AM
SpringFan25
find the expected value for one game, then multiply it by 50. Post again if you dont understand why that works.
• May 10th 2011, 11:50 AM
jillby
Thanks SpringFan25..... That worked and I do understand why. I was trying to overcomplicate it since I didn't have any potential loss values.