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Math Help - Poisson

  1. #1
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    Poisson

    During business hours, the number of calls passing through a particular cellular relay system averages 5 per minute.

    (a)
    Find the probability that no call will pass through the relay system during a given minute.
    P(X=0)=p(0)=\frac{5^0}{0!}e^{-5}=.0067

    (b)
    Find the probability that no call will pass through the relay system during a given 2 minute period.
    [P(X=0)]^2=[p(0)]^2=\frac{5^0}{0!}e^{-10}=.0000454
    Not so sure about this one.

    (c)
    Find the probability that 3 calls will pass through the relay system during a given minute.
    P(X=3)=p(3)=\frac{5^3}{3!}e^{-5}=.1404

    Correct?
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  2. #2
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    all fine

    For 2, you can also note that the number of calls in a t minute period is poisson( \lamda * t) . (you end up with exactly the same calculation)
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