Thread: Sample Size Estimate

Hi Everyone, I have a problem, and I'm not too sure how to do or even approach it.

imgur: the simple image sharer

Any light you can shed is greatly appreciated.
Thanks!

Now the mean is normally distributed with mu = 2 and sigma = 2, this should be clear.

The distribution of the mean is therefore mu plus/minus Z times sigma/sqrt[n]. For the bounds given you need to back solve for n.