Hi Everyone, I have a problem, and I'm not too sure how to do or even approach it.

imgur: the simple image sharer

Any light you can shed is greatly appreciated.

Thanks!

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- April 25th 2011, 12:41 PMprobabilitystudentSample Size Estimate
Hi Everyone, I have a problem, and I'm not too sure how to do or even approach it.

imgur: the simple image sharer

Any light you can shed is greatly appreciated.

Thanks! - April 25th 2011, 06:26 PMpickslides
Now the mean is normally distributed with mu = 2 and sigma = 2, this should be clear.

The distribution of the mean is therefore mu plus/minus Z times sigma/sqrt[n]. For the bounds given you need to back solve for n.