I am trying to find the odds/probability of rolling all three dice and it resulting in a Double:
a) Two regular dice with 1,2,3,4,5,6 on the faces
b) A third six sided dice with the following on the faces: 1,blank,blank,blank,6,6
My math skills are poor, so any help would be appreciated.
thanks in advance.
Okay, I have the following possibilities:
a: b: c:
1 1 x
1 x 1
x 1 1
2 2 x
3 3 x
4 4 x
5 5 x
6 6 x
6 x 6(y)
x 6 6(y)
6 x 6(z)
x 6 6 (z)
So, it's possible to get 12 doubles. I am probably coming across here as a thicko, I just cannot do maths, so I am not sure how to work out the probability and odds.
Since you have named the dice a, b and c and listed the outcomes for each, clearly the red events I highlighted are NOT included. You need to think carefully why ( I suggest you consider what happens with only two dice to understand this). You have listed other events - which I haven't highlighted - which should also NOT be included. It is your job to get an accurate list.
The probability of the event (1, 1, x) is (1/6)(1/6)(4/6) = .....
Other events are similarly calculated.
Then you add up the probabilities to get a total probability.