P(gets at least 1 right) = 1 - P(gets none right)
can you work out P(gets none right) ?
An unprepared student makes random guesses for 6 multiple choice questions that have selections a - e. Find the probability that there is at least one correct answer.
A) .672
B) .200
C) .738
D) .800
Now i don't want the answer i just would like to know how to figure it out any help would be very much appreciated.
Rule #9: http://www.mathhelpforum.com/math-he...hp?do=vsarules New question - new thread.