That seems like a really complicated way to look at an easy question that has been worded very difficultly.

I prefer tree-diagrams

(apologies for the bad drawing)

Just follow the path that is relevant.

First, it asks about the husband - You are looking for the husband to be watching TV.. correct?

In this case, start at the left-hand side and follow the 'branch' up towards the a. 60% (watching)

Next, it asks about the wife.

When the Husband is watching TV, she must be watching at the same time.

So, next - continue up along that path to a. 40% (watching)

Now, all you need to do is multiply the %'s that you had on the way -

ie,

60% $\displaystyle \cdot$ 40% --- ie, find 40% of 60% [of 100]

or, if you prefer it like this:

$\displaystyle \frac {60}{100} \cdot \frac{60}{100} = \frac {6}{10} \cdot \frac{4}{10} = 0.6 \cdot 0.4 = 0.24$

Therefore, there is a 0.24 (24%) possibility of having the Husband AND Wife watching tv at the same time

a.) Find the probability that if the wife is watching TV then the husband is also.

Assuming that should read WHEN the husband is also, this sounds about right