if 5 card are dealt from 52 cards, determine the probabilty of getting 3 red cards and 2 black face cards.

The answer is 26C3(6C2)/52C5, but I got 52C5(1/2)^5(6/52)^2, how do you know when to use which?

Thank you!

Results 1 to 2 of 2

- August 11th 2007, 10:33 PM #1

- Joined
- Aug 2007
- Posts
- 4

- August 12th 2007, 04:26 AM #2

- Joined
- May 2006
- From
- Lexington, MA (USA)
- Posts
- 11,946
- Thanks
- 798

Hello, wby!

If 5 cards are dealt from 52 cards,

determine the probabilty of getting 3 red cards and 2 black face cards.

The answer is: .

but I got: . .**??**

How do you know when to use which?

That is the number of possible 5-card hands.

. . It belongs in the*denominator.*

When they state "Five cards are dealt",

. . we generally assume it is__without__replacement.

So the probability of getting a certain color is__not__each time,

. . and the probability of getting a black face card is__not__each time.

Their answer is correct.

You want to draw 3 red cards from the available 26 red cards.

. . There are: . ways.

You want to draw 2 black face cards from the available 6 black face cards.

. . There are: . ways.

. . Hence, there are: . ways to draw 3 red cards and 2 black face cards.

And that is over , the number of possible 5-card hands.