Hi guys.

Here is a probability question.

Let:

f(d, w) = p(d, w);
f (d, w) = p(d,w)p(d|d)p(w|w)=p(d,w) {p(d)/ p(d)}{p(w)/ p(w)};
f (d) = sum_w {f(d, w)};
f (d)= sum_w { f (d, w)};
f(d|w) = f(d, w) / f(w);
f (d | w) = f ( d, w) / f (w)


To Show: p(w | d) p(w | w) = f ( w | d );



Thanks!