I am totally lost....

I changed the problem around a bit, but it is similar in form to this, on my homework.

Image - TinyPic - Free Image Hosting, Photo Sharing & Video Hosting

How would I go about solving this?

Thanks,

Thomas

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- Mar 29th 2011, 03:36 AMTomHillson4Normal Probability Distributions....
I am totally lost....

I changed the problem around a bit, but it is similar in form to this, on my homework.

Image - TinyPic - Free Image Hosting, Photo Sharing & Video Hosting

How would I go about solving this?

Thanks,

Thomas - Mar 29th 2011, 05:04 AMSpringFan25
the absolute value of something |Z|, is always equal to Z or -Z.

So

$\displaystyle P(|Z| > 1) = P(Z > 1) + P(-Z > 1)$

ie, the absolute value of Z is greater than one if Z>1, or -Z > 1.

try applying this to your problem and post again if you are stuck.