Thread: Factorizing

I am trying to compete with my teenage daughter.

Question:

In a 6 figure number where the first number cannot be zero but the other five
can be any number, how many different 6 figure numbers can there be ?
Also I would like the formula for calculating same.

Consider the amount of possible outcomes.

For example for a three digit number it is 9 * 10*10

Yes but what is the answer and what is the formula. I am just a simple father.

Originally Posted by divorce4

Yes but what is the answer and what is the formula. I am just a simple father.

There are N-digits positive integers which do not begin with zero.

Does that help?

There are 999999 six digit numbers. The first 99999 of them have a leading 0 so 999999- 99999 of them do not have a leading 0.

What is this competition with your daughter? To see who can first get someone else to do the problem for them?

(And why was this titled "factorizing"?)