It depends on what lottery you're talking about
If the lottery is such that 14 million tickets are printed each with a different number on it, and at the end the winning ticket is selected at random, then the odds of any ticket being picked are a million to one, and if you have 2 tickets the odds that one of these two tickets will be picked is 14 million to 2, or 7 million to one.
However, since you brought up the "14 million to 1" number, I assume you're talking about the 6:49 lottery, where 6 numbers are selected at "random" from a pool of 49 different numbers, and thus the odds of any combination of being the winning one is 13 983 816, which is the total amount of combinations of 6 numbers you can make with 49 numbers. (49 C 6 = 13 983 816)
Now in this situation, you could say that every DIFFERENT combination of 6 numbers selected from 49 has exactly the same odds of winning. So for your odds of winning to increase with every ticket, you have to put a different number on each one. Indeed, if I have 13 983 816 tickets each with a different combination on it, then I have ALL combinations so I'm guaranteed to win.
The only possible objection I could imagine is if you have a different definition of "winning". So far we have considered winning having the 6 numbers match, but with some lotteries you can win smaller prizes if you get 2, 3, 4 or 5 numbers right. In this case, the odds of "winning" as a broad term has completely different odds.