A six sided die is rolled twice. What is the probability of rolling an even number on the first roll OR a 1 on the second roll? The answer is 7/12 but for the life of me I can't figure this out working backwards/forwards/sideways you name it. Ty
A six sided die is rolled twice. What is the probability of rolling an even number on the first roll OR a 1 on the second roll? The answer is 7/12 but for the life of me I can't figure this out working backwards/forwards/sideways you name it. Ty
Hi LostInTheSauce, great username....
I call recall a few times where this happened to me!
Anyhow back to the question, let the ordered pair (x,y) be the result of x the first roll and y be the second roll.
Map out all the possibilities.
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)
How many have a even number on the x or a 1 on the y?