Two fair dice are thrown. Prob of event A.
Hi to all.
Simple question but answer seems to be coming wrong.
Two fair dice are thrown.
(i) Event A is ‘the scores differ by 3 or more’. Find the probability of event A.
(ii) Event B is ‘the product of the scores is greater than 8’. Find the probability of event B.
When it says the scores differ by 3 or more, what I understand is that the difference of the results should be 3 or more. This means 3,4,5 and 6. So, won't we have the following pairs:
For difference of 3: (6,3) (5,2) (4,1) and Reverse.
For difference of 4: (6,2) (5,1) and Reverse.
For difference of 5: (6,1) and Reverse.
For difference of 6: None.
So we'd have (1/6)^6 + (1/6)^4 + (1/6)^2 ...? The answer I get is 1333/46656 which appears to be wrong. Maybe I didn't get the question right. So any help here?
Part (ii) likely has the same problem.