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Math Help - Probability

  1. #1
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    Probability

    Hi,

    I am new to this forum. Pls help with my problem.

    What is the chance that an ordinary year selected at random contains53 Sundays.

    How to work it.

    Regards,
    Suganya
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  2. #2
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    Hello, suganya!

    What is the chance that an ordinary year selected at random contains 53 Sundays?

    An "ordinary" year has 365 days.

    Note that: . 365 \:=\:52(7) + 1
    . . That is, a year has 52 full weeks plus one day.

    This means that a year begins on a certain weekday
    . . and also ends on the same weekday.

    Hence, a year starting on Sunday will have 53 Sundays.

    Assuming the starting day for a year is evenly distributed,
    . . the probability of beginning on a Sunday is \frac{1}{7}

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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by Soroban View Post
    Hello, suganya!


    An "ordinary" year has 365 days.

    Note that: . 365 \:=\:52(7) + 1
    . . That is, a year has 52 full weeks plus one day.

    This means that a year begins on a certain weekday
    . . and also ends on the same weekday.

    Hence, a year starting on Sunday will have 53 Sundays.

    Assuming the starting day for a year is evenly distributed,
    . . the probability of beginning on a Sunday is \frac{1}{7}
    But does the existance of leap years alter this?

    RonL
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