Thread: Need direction - Hypothesis Testing

1. Need direction - Hypothesis Testing

I've worked through a set of practice questions and ran across this problem and don't see how I can solve it without $\sigma$. Can someone please give me some direction?

Q: When someone dials 911 for an emergency, the average length of time to reach an operator is supposed to be no more than 30 seconds. However, in a recent survey of 81 such calls, the sample mean came out to be 32 seconds. Is the response time in fact too long? Use $\alpha$=.10

So, $\mu_0$=30, $n$=81, and $\bar{x}$=32.
$H_o$: $\mu=30$, and
$H_a$: $\mu>30$.

I wanted to use the Z or T test statistics but I guess I can't because I don't see that I'm provided with enough information to be able to use them.

I really appreciate your help! I'm sure there is something basic that I'm not seeing.

2. I would venture to guess that is a poisson rv and thus the variance is the same as the mean.
(By the way I never sleep)
If these are Poisson's then you have as n goes to infinity

${\bar X-\mu\over \sigma/\sqrt{n}}\to N(0,1)$

but we can use the Law of Large Numbers and Slutsky's Theorem.
There we have $\sigma^2=\mu=\lambda$

So If this is a Poisson we can use either $\bar X$ as estimate of $\sigma^2$
or use the null hypothesis value as the estimate of the unknown variance.

I'm making this guess since n is greater than 30 so I would guess they want to use the CLT.
And if there isn't a sigma, we need to find a relationship between moo and sigma.

Night Poisson Ivy

3. Hi MathEagle!
It also seemed to me that the problem may involve a Poisson RV. But how can I argue that when I'm not given any time intervals or such?

Thanks! It's great to hear from you!

-Poisson Ivy

4. maybe they just left out sigma?
so, how is Charms doing?
are you in school?