This is some really basic stuff, I'm sure. It's for a Calculus based probability course. I can't really see what's going on in class (I'm quite literally legally blind), and the instructor doesn't really have any online resources available.
The site (or my internet connection) is being goofy and won't let me upload the file. I'll have to link to it.
ImageShack® - Online Photo and Video Hosting
I've drawn a probability tree and concluded that there is a 10% chance of a fair coin landing on heads three consecutive times for number 1.
After that problem, I'm clueless of where to go. I'm not even sure I'm right on it. Any resources for this type of problem would be greatly appreciated. Thank you.
I'm failing to see how it doens't make sense. The two-headed coin is not relevant in this problem. When the probability of the two-headed coin landing on heads three times consecutively is removed, you're left with (4/5)(1/2)^3, which is exactly what I said.
The two-headed coin is not a fair coin. Its probability of 20% is not relevant because it does not satisfy the condition of being a fair coin.
Edit: I had the wrong idea. In this case, the probability it is a fair coin is 1/3, as opposed to the 2/3 chance of a two-headed coin.