if a b c are three natural numbers in Arithmetic progression and a+b+c=21 then all the possible values of the ordered triplet (a,b,c) is
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If they are in arithmetric progression, a, b and c have a common difference, or: Then; I think that should be okay to solve now.
Originally Posted by prasum if a b c are three natural numbers in Arithmetic progression and a+b+c=21 then all the possible values of the ordered triplet (a,b,c) is Your AP is so . That means that . The numbers of pairs that satisfy that depends on if we consider 0 a natural or not. Here is an example: then the AP is . Can you finish?
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