What group is the median in?
How do I work this out?
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Count the total 9 + 16 + 20 + 16 + 6 + 5 = 72
Now count the frequences of t
below 30 = 9
below 40 = 9 + 16
below 50 = 9 + 16 + 20
The group with the median will be the first where the total amount below exceed half of the total (1/2 * 72)
I have another question that is to do with the table.
When the frequencies are converted to angles for the associated pie chart, the frequency value of 16 is converted into an angle, in degrees, of?
A whole circle 360 degrees represents the total: 72
72 is to 360 degrees as 16 is to _ degrees?
Setup the ratio.
How do I work it out??
72/360 = 16/x
x = 360 * 16 / 72 degrees.
You can add an extra column to your table 'relative frequency' which will be the % each bin represents. Then apply this % to 360, that will give the answer.
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