http://aces.shu.ac.uk/staff/cmsrm2/C...CQ4_Prelim.gif

What group is the median in?

How do I work this out?

Thanks

Printable View

- Jan 10th 2011, 12:11 PMmathsnubMedian help
http://aces.shu.ac.uk/staff/cmsrm2/C...CQ4_Prelim.gif

What group is the median in?

How do I work this out?

Thanks

- Jan 10th 2011, 12:18 PMsnowtea
Count the total 9 + 16 + 20 + 16 + 6 + 5 = 72

Now count the frequences of t

below 30 = 9

below 40 = 9 + 16

below 50 = 9 + 16 + 20

...

The group with the median will be the first where the total amount below exceed half of the total (1/2 * 72) - Jan 10th 2011, 12:32 PMmathsnub
Thank you.

I have another question that is to do with the table.

When the frequencies are converted to angles for the associated pie chart, the frequency value of 16 is converted into an angle, in degrees, of? - Jan 10th 2011, 12:35 PMsnowtea
A whole circle 360 degrees represents the total: 72

72 is to 360 degrees as 16 is to _ degrees?

Setup the ratio. - Jan 10th 2011, 12:38 PMmathsnub
How do I work it out??

thx - Jan 10th 2011, 12:46 PMsnowtea
72/360 = 16/x

x = 360 * 16 / 72 degrees. - Jan 10th 2011, 12:54 PMpickslides
You can add an extra column to your table 'relative frequency' which will be the % each bin represents. Then apply this % to 360, that will give the answer.