1. ## probability(urgent)

(i) You draw 2 cards from a deck of 52 cards and the return as follow:

Result
How much you win
Blackjack or Double Aces
$50 Total is more than 16$10
Done of the above
- $5 (Assume the face value of an ace is 11) (a) A man rolls a die for 10 times, find the probability that (i) he gets 2 sixes, given that he gets 2 fives. (ii) he doesn’t get the same number consecutively. (i) Besides receive the prize, a visitor who spent more than 2 hours in the casino would receive an envelope with coupon. Coupons in envelopes were numbered 1 to 5, and a set of one of each was required for applying the VIP card. Assume all numbers are equally probable, with one coupon per envelope, how many envelopes on the average were required to apply the VIP card? 2. Originally Posted by pplteo (i) You draw 2 cards from a deck of 52 cards and the return as follow: Result How much you win Blackjack or Double Aces$50
Total is more than 16
$10 Done of the above -$5

(Assume the face value of an ace is 11)

(a) A man rolls a die for 10 times, find the probability that
(i) he gets 2 sixes, given that he gets 2 fives.
(ii) he doesn’t get the same number consecutively.

(i) Besides receive the prize, a visitor who spent more than 2 hours in the casino would receive an envelope with coupon. Coupons in envelopes were numbered 1 to 5, and a set of one of each was required for applying the VIP card. Assume all numbers are equally probable, with one coupon per envelope, how many envelopes on the average were required to apply the VIP card?
your first question is the same one as another user asked i believe. see here

Originally Posted by pplteo

(a) A man rolls a die for 10 times, find the probability that
(i) he gets 2 sixes, given that he gets 2 fives.
(ii) he doesn’t get the same number consecutively.

(i) Besides receive the prize, a visitor who spent more than 2 hours in the casino would receive an envelope with coupon. Coupons in envelopes were numbered 1 to 5, and a set of one of each was required for applying the VIP card. Assume all numbers are equally probable, with one coupon per envelope, how many envelopes on the average were required to apply the VIP card?
see this post

Originally Posted by pplteo
(i) You draw 2 cards from a deck of 52 cards and the return as follow:

Result
How much you win
Blackjack or Double Aces
$50 Total is more than 16$10
Done of the above
- $5 (Assume the face value of an ace is 11) (a) A man rolls a die for 10 times, find the probability that (i) he gets 2 sixes, given that he gets 2 fives. (ii) he doesn’t get the same number consecutively. (i) Besides receive the prize, a visitor who spent more than 2 hours in the casino would receive an envelope with coupon. Coupons in envelopes were numbered 1 to 5, and a set of one of each was required for applying the VIP card. Assume all numbers are equally probable, with one coupon per envelope, how many envelopes on the average were required to apply the VIP card? also see here hopefully all these posts will get your questions answered. i believe these EXACT questions were asked by other users, so you can just browse through them to see what questions you have in common 3. Originally Posted by Jhevon also see here hopefully all these posts will get your questions answered. i believe these EXACT questions were asked by other users, so you can just browse through them to see what questions you have in common thank u very much.. but the last question don have the answer i want can u help me? 4. Originally Posted by Jhevon also see here hopefully all these posts will get your questions answered. i believe these EXACT questions were asked by other users, so you can just browse through them to see what questions you have in common Originally Posted by Jhevon your first question is the same one as another user asked i believe. see here . . how to write in the binomial probability 5. Originally Posted by pplteo thank u very much.. but the last question don have the answer i want can u help me? i would love to help, but you should wait on one of the other posters who posted in the threads i directed you to. Probability is not my strong point 6. Originally Posted by pplteo how to write in the binomial probability It is not binomial! But one could write it as$\displaystyle \frac{{10!}}{{3!3!4!}}\left( {\frac{1}{6}} \right)^3 \left( {\frac{1}{6}} \right)^3 \left( {\frac{4}{6}} \right)^4\$ .