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Thread: Probability check

  1. #1
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    Probability check

    I had an assignment and I got this part of equation:
    $\displaystyle P^4*(1-P)^0$

    Is it correct how I solved it ?
    $\displaystyle = P^4-P^4$
    remember the Power is 0
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  2. #2
    MHF Contributor chisigma's Avatar
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    No matter which is $\displaystyle a$ is $\displaystyle a^{0}=1$ , so that...
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  3. #3
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    so was it correct?
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  4. #4
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    Quote Originally Posted by Mathematicsfan View Post
    so was it correct?
    How did you obtain $\displaystyle P^4-P^4\;\;?$
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  5. #5
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    Quote Originally Posted by Mathematicsfan View Post
    I had an assignment and I got this part of equation:
    $\displaystyle P^4*(1-P)^0$

    Is it correct how I solved it ?
    $\displaystyle = P^4-P^4$
    remember the Power is 0
    There is a difference between

    $\displaystyle P^4(1-P)^0$

    and

    $\displaystyle P^4\left(1-P^0\right)$
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