Originally Posted by

**TP123** Lets say there's a game that involves a 40 card deck without any face cards. And to win this game the player has to pick 4 cards and if they pick a 4 card hand of all one suit they win ex.(2 of hearts, 5 of hearts, 7 of hearts, 9 of hearts).

The probability of this would be 4(10c4/40c4) = 840/91390.

And lets say another way of winning this game would be to get a hand of all red cards. ex.(6 hearts, 4 diamonds, 3 hearts, 8 diamonds).

The probability of getting this hand would be (20c4)/(40c4)= 4845/91390.

Since the 2 ways of winning overlap each other, you could get the same hand from both calculations so what should I minus the equation of P(4 red cards) by to find the probability of winning? How should the end equation look like?