# Probability help request

• Jan 5th 2011, 12:40 AM
Mathematicsfan
Probability help request

-It's known that if 6 employees of a huge factory are being checked then the probability that at the most 5 of them smoke is bigger in 0.764702 from the probability that all 6 employees smoke.
A- What is the probability that all 6 are smoking?

• Jan 5th 2011, 12:53 AM
mr fantastic
Quote:

Originally Posted by Mathematicsfan

-It's known that if 6 employees of a huge factory are being checked then the probability that at the most 5 of them smoke is bigger in 0.764702 from the probability that all 6 employees smoke.
A- What is the probability that all 6 are smoking?

You are told that $\displaystyle \Pr(X \leq 5) = \Pr(X = 6) + 0.764702$.

But $\displaystyle \Pr(X \leq 5) = 1 - \Pr(X = 6)$.

Therefore $\displaystyle 1 - \Pr(X = 6) = \Pr(X = 6) + 0.764702$ ....
• Jan 5th 2011, 01:59 AM
Mathematicsfan
Is there any way to solve it otherwise ? this method I didn't study yet.
we are asked to solve it according to Bernoulli's table.
• Jan 5th 2011, 11:57 AM
mr fantastic
Quote:

Originally Posted by Mathematicsfan
Is there any way to solve it otherwise ? this method I didn't study yet.
we are asked to solve it according to Bernoulli's table.

It would help if you included information like that in the original posting of the question.

I have not used some special 'method'. It is a basic application of a basic fact in probability. Surely you have met such facts .... And surely you can solve an equation of the form 1 - x = x + 0.764702.

I don't see the point in doing it the way you have apparently been told to. Maybe someone else has the time and the inclination.