# help finding probability again,please let me know if I did it right

• Jul 8th 2007, 01:29 PM
mkcar
help finding probability again,please let me know if I did it right
the question is
you roll a die. find each probability
A. rolling a 6 or a number greater then 4.
B. Rolling a number less then 5 or an odd number
c. rolling a 3 or an even number
I think I have it right but would like you experts to help. thank you
• Jul 8th 2007, 01:34 PM
Jhevon
Quote:

Originally Posted by mkcar
I think I have it right but would like you experts to help. thank you

• Jul 8th 2007, 01:38 PM
janvdl
Quote:

Originally Posted by mkcar
the question is
you roll a die. find each probability
A. rolling a 6 or a number greater then 4.
B. Rolling a number less then 5 or an odd number
c. rolling a 3 or an even number
I think I have it right but would like you experts to help. thank you

For a)

The chances of rolling a 6 are $\frac{1}{6}$ i think.

Rolling a number greater than 4. It should be either 5 or 6 then, but we already have 6 so it will be only 5 that is left $\frac{1}{6}$

$\frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3}$

For b)

Rolling a number less than 5. It should be 1;2;3 or 4 then, so it will be $\frac{4}{6}$

An odd number. It should be 1;3 or 5 then, but we already have 1 and 3. Only 5 remains, so it will be $\frac{1}{6}$

$\frac{4}{6} + \frac{1}{6} = \frac{5}{6}$

For c)

The chances of rolling a 3 are $\frac{1}{6}$

An even number. It should be 2;4 or 6 then, so it will be $\frac{3}{6}$

$\frac{1}{6} + \frac{3}{6} = \frac{4}{6} = \frac{2}{3}$

Quote:

Originally Posted by mkcar
I think I have it right but would like you experts to help...

That's not me. :D Probability isnt my strong point. :D Jhevon helped me, so give him credit... I made mistakes.
• Jul 8th 2007, 01:44 PM
mkcar
Thank you, I had a part wrong