the question is

you roll a die. find each probability

A. rolling a 6 or a number greater then 4.

B. Rolling a number less then 5 or an odd number

c. rolling a 3 or an even number

I think I have it right but would like you experts to help. thank you

- Jul 8th 2007, 12:29 PMmkcarhelp finding probability again,please let me know if I did it right
the question is

you roll a die. find each probability

A. rolling a 6 or a number greater then 4.

B. Rolling a number less then 5 or an odd number

c. rolling a 3 or an even number

I think I have it right but would like you experts to help. thank you - Jul 8th 2007, 12:34 PMJhevon
- Jul 8th 2007, 12:38 PMjanvdl
**For a)**

The chances of rolling a 6 are $\displaystyle \frac{1}{6} $ i think.

Rolling a number greater than 4. It should be either 5 or 6 then, but we already have 6 so it will be only 5 that is left $\displaystyle \frac{1}{6} $

Add them together.

$\displaystyle \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3} $

**For b)**

Rolling a number less than 5. It should be 1;2;3 or 4 then, so it will be $\displaystyle \frac{4}{6} $

An odd number. It should be 1;3 or 5 then, but we already have 1 and 3. Only 5 remains, so it will be $\displaystyle \frac{1}{6} $

Add them together.

$\displaystyle \frac{4}{6} + \frac{1}{6} = \frac{5}{6} $

**For c)**

The chances of rolling a 3 are $\displaystyle \frac{1}{6} $

An even number. It should be 2;4 or 6 then, so it will be $\displaystyle \frac{3}{6} $

Add them together.

$\displaystyle \frac{1}{6} + \frac{3}{6} = \frac{4}{6} = \frac{2}{3} $

Quote:

Originally Posted by**mkcar**

- Jul 8th 2007, 12:44 PMmkcarThank you, I had a part wrong
thank you all for your help I had a part wrong.