
Hypothesis Testing
A biologist discovers a colony of a previously unknown type of bird nesting in a cave. Out of the 16 chicks which hatch during his period of investigation, 13 are female. Test at the 5% significance level whether this supports the view that that the sex ratio for the chicks differs from 1.
Im really stuck i think ive developed the p:H1 and p:H0 but after that i am a bit stuck any help is much appreciated thankyou

Sounds like you should use a $\displaystyle \displaystyle \chi^2$ test here.
$\displaystyle \displaystyle H_0:$ Observed sex ratio can be described by the Expected sex ratio
$\displaystyle \displaystyle H_1:$ Observed sex ratio differs from the Expected sex ratio
Now you need to make a table
$\displaystyle \begin{array}{ccc}
& \text{Male} & \text{Female}\\ \hline
\text{Expected} & \dots & \dots \\ \text{Observed} & \dots & \dots \\ \chi^2_{calc} & \dots & \dots\\ \hline \end{array}$
Populate this table and find $\displaystyle \displaystyle \chi^2_{calc} = \Sum \frac{(\text{0bservedExpected})^2}{\text{Expected}}$
If $\displaystyle \displaystyle \chi^2_{calc} > \chi^2_{crit}= \chi^2_{df,\alpha}$ reject $\displaystyle \displaystyle H_0$

I would test that the proportion of females is .5 versus not
Since n is small you cannot approximate with a normal and you will need to use the binomial distribution.
You can obtain the pvalue with x=13
And n=16, p=.5.