# Thread: probability with cards(not 52)

1. ## probability with cards(not 52)

If I have a deck of 60 cards, and a set within that deck of 16 similar cards(you might call it a suit for simplicity's sake), how would i find the probability of drawing at least one of those cards in an initial hand of seven(not replacing the cards after drawing them)?

2. A lot of times, the best way to do a 'at least' problem is to find the probability of none and then subtract from 1. Because none is the opposite of at least one.

There are 44 cards not of your 'suit'. The probability of drawing 7 of those is

$\frac{C(44,7)}{C(60,7)}$

So, the proability of drawing at leat 1 of the 16-card suit is

$1-\frac{C(44,7)}{C(60,7)}=0.90$