I know what the answer to this is, but I haven;t got a clue how to arrive at it. Could someone please explain how I would approach this kind of problem?
Thanks.
Let $\displaystyle (x_1,x_2,...,x_n)$ $\displaystyle n$ numbers is increasing order (or non-decreasing). If $\displaystyle n$ is odd then $\displaystyle x_{\frac{n+1}{2}}$ is the location of the median. If even then $\displaystyle \mbox{Average}\left( x_{\frac{n}{2}}, x_{\frac{n+1}{2}} \right)$.
Since you have $\displaystyle n=100$ the answer is the average between the 50th and the 51st number when placed in increasing order.