I know what the answer to this is, but I haven;t got a clue how to arrive at it. Could someone please explain how I would approach this kind of problem?

Thanks.

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- July 3rd 2007, 04:36 AMGAdamsMedian
I know what the answer to this is, but I haven;t got a clue how to arrive at it. Could someone please explain how I would approach this kind of problem?

Thanks. - July 3rd 2007, 07:35 AMThePerfectHacker
Let numbers is increasing order (or non-decreasing). If is odd then is the location of the median. If even then .

Since you have the answer is the average between the 50th and the 51st number when placed in increasing order. - July 3rd 2007, 12:58 PMCaptainBlack
The median is in the interval 10<=x<20m as there are 31 of 100 for x<10, and 55 of 100 for x<20, so the median is in the range 10<=x<20.

RonL