# Thread: A card is drawn from a standard deck. Not red or ace?

1. ## A card is drawn from a standard deck. Not red or ace?

A card is drawn from a standard deck of playing cards. What is the probability that it will not be a red or ace?

My Solution (which seems to be incorrect):

I would say, the probability that it's red is 1/2
The probability that it's ace is 4/52. On the other hand, there are two ace cards which are Red and already counted so I would say (4-2)/52 = 2/52

so 1 - (1/2 + 2/52) = 1 - 0.53 = 0.47

Is this correct? How to solve this problem in the form of C(n,m)?

Thank you

2. Of the 52 cards, there are 26 that are red and 2 other aces. So that means that there are 28 that are red or an ace.

So what's the probability of not getting red or an ace?

3. Originally Posted by Prove It
Of the 52 cards, there are 26 that are red and 2 other aces. So that means that there are 28 that are red or an ace.

So what's the probability of not getting red or an ace?
That is 1 - (28/52) = 24/52 = 0.46 ~~~ hmmmmm

4. Correct.