A card is drawn from a standard deck. Not red or ace?

A card is drawn from a standard deck of playing cards. What is the probability that it will not be a red or ace?

My Solution (which seems to be incorrect):

I would say, the probability that it's red is 1/2

The probability that it's ace is 4/52. On the other hand, there are two ace cards which are Red and already counted so I would say (4-2)/52 = 2/52

so 1 - (1/2 + 2/52) = 1 - 0.53 = 0.47

Is this correct? How to solve this problem in the form of C(n,m)?

Thank you (Speechless)