i can not figure out since i don't know it's normally distributed or not?
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You can do a test for normality but you need the raw data which in this case looks unavailable. What impact would the C.L.T. have in this question? Have you thought to use a different distribution i.e. binomial?
Originally Posted by pickslides You can do a test for normality but you need the raw data which in this case looks unavailable. What impact would the C.L.T. have in this question? Have you thought to use a different distribution i.e. binomial? i did solve part b) using binomial theorem and i got the answer of 0.9713 but in part a) i can not use binomial since np is less than 5.
Originally Posted by Jattboyz i did solve part b) using binomial theorem and i got the answer of 0.9713 but in part a) i can not use binomial since np is less than 5. "if" you are using the binomial approximation to the Normal. For part (a) you have the 2-day probability figure... $\displaystyle (p+q)^5=\binom{5}{5}p^5+\binom{5}{4}p^4q+.....$ The probability that all 5 are returned by Monday is $\displaystyle p^5=0.8^5$
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