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Math Help - Distribution Problem

  1. #1
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    Distribution Problem

    I have a question on a take-home that asks:

    Find a value such that (X is normally distributed rv) :

    P (μ -σ < X< μ + βσ) = 0.95

    I must be doing something wrong, though, because from everything I can tell, this is impossible.

    When standardized, this would lead to:


    z1= x-μ /σ = μ -σ - μ / σ = -1

    leading me to:

    P(z< z2) = 0.95 + P(z < -1)

    0.95 + P(z < -1) has a value of greater than 1, which is obviously impossible. Am I doing this wrong, or does this question have no answer?

    Thank you for your help, in advance!

    Futant.
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  2. #2
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    Quote Originally Posted by Futant View Post
    I have a question on a take-home that asks:

    Find a value such that (X is normally distributed rv) :

    P (μ -σ < X< μ + βσ) = 0.95

    I must be doing something wrong, though, because from everything I can tell, this is impossible.

    When standardized, this would lead to:


    z1= x-μ /σ = μ -σ - μ / σ = -1

    leading me to:

    P(z< z2) = 0.95 + P(z < -1)

    0.95 + P(z < -1) has a value of greater than 1, which is obviously impossible. Am I doing this wrong, or does this question have no answer?

    Thank you for your help, in advance!

    Futant.
    Please read rule #6 here: http://www.mathhelpforum.com/math-he...ng-151418.html

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