The question is about the telephone company. There are 10000 possible numbers from 805-0000 to 805-9999. If they select the numbers with equal probability what is the probability that the number selected will end in 333?
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Well, how many numbers in that range look 805-X333?
0333, 1333, 2333, 3333,4333,5333,6333,7333,8333,9333 10? so that means the probability is 10/10000?
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