A certain airplane holds 184 passengers. The rate of passengers' no-show is 9% and they sell 201 tickets. Is it likely that they will not have enough seats. It seems easy but i'm stuck
A certain airplane holds 184 passengers. The rate of passengers' no-show is 9% and they sell 201 tickets. Is it likely that they will not have enough seats. It seems easy but i'm stuck
Let X be the random variable "number of passengers who show up".
X ~ Binomial(n = 201, p = 0.91). Calculate $\displaystyle \Pr(X \geq 185)$ and draw a conclusion.