Could someone help me with this question ; it would be much appreciated

Ivan and Jo are chess players. In any game the probabilities of Ivan beating Jo, Jo beating Ivan or the game resulting in a draw are 0.6. 0.1 or 0.3 respectively. They play a series of three games. Calculate the probability that:

a) The three games are drawn

b) They win alternate games with Ivan winning the first one

c) Exactly 2 of the 3 games are drawn

d) Joe does not win a game

I'm not sure if this is right but for

a) i just did 0.3 ^ 3

and for

b) 0.6 * 0.1 * 0.6

So yeah, if anyone could assist me on these, it would be great