So, yes, it's right!
where D represents the even that the game is a draw.
Could someone help me with this question ; it would be much appreciated
Ivan and Jo are chess players. In any game the probabilities of Ivan beating Jo, Jo beating Ivan or the game resulting in a draw are 0.6. 0.1 or 0.3 respectively. They play a series of three games. Calculate the probability that:
a) The three games are drawn
b) They win alternate games with Ivan winning the first one
c) Exactly 2 of the 3 games are drawn
d) Joe does not win a game
I'm not sure if this is right but for
a) i just did 0.3 ^ 3
b) 0.6 * 0.1 * 0.6
So yeah, if anyone could assist me on these, it would be great