If a(x) is a function whose expectation exists, and if , then So i did this: And do the same for discrete cases.... Is this correct?
Last edited by chutiya; October 31st 2010 at 01:26 PM.
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Originally Posted by chutiya a is a function of x so how can you do this? Originally Posted by chutiya And do the same for discrete cases.... In discrete cases use a summation.
Originally Posted by pickslides a is a function of x so how can you do this? In discrete cases use a summation. Because my book did something similar..For a function a, whose expectation exists: Looking at this from the book, I thought of doing what I mentoined above. By Discrete cases, I meant doing the same process using the summation sign. If thats wrong, how do I prove it?
I see, your book has taken out k as a constant, but the function a of x remained. It cannot be removed from the intergrand useless this is also constant. It does not say this anywhere in the question.
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