How many tonnes are there in all?
How much time are there in all?
From this, can you find out how much time one tonne is kept in store using proportions.
X tonnes --> Y days
1 tonne --> ? days
I need to work out the average length of time that a Farmer keeps a tonne of potatoes in his store. I have been given the following monthly stock figures and need to work this out. probably very simple but having a mind blank - help please.
Month Tonnes in Store
To, take the total of all of them.
October through June, you have (31 + 30 + 31 + 31 + 28 + 31 + 30 + 31 + 30) = 273 days.
In all, you have (2110 + 2010 + 1910 + 1710 + 1610 + 1185 + 885 + 445 + 0) = 11865 tonnes.
11865 tonnes --> 273 days.
1 tonne --> 273/11865 = 0.023 days = 33 minutes
Perhaps I have not explained myself properly. The farmer only sells 100 tonnes of his total 2110 in the first month (30days). This means the minimum length of time a tonne is in store is 30 days, the maximum being the full 8 months. However, as the quantities in store to not reduce at the same rate over time (he sells less at the start and more of them in the later months), it is not as simple as just averaging the time.
I hope this explains my problem better.
We can make a table for that then?
Then, from that we get:
100 tonnes kept for 31 days
100 tonnes kept for 61 days
200 tonnes kept for 92 days
100 tonnes kept for 123 days
425 tonnes kept for 151 days
300 tonnes kept for 182 days
440 tonnes kept for 212 days
445 tonnes kept for 243 days
This gives an average of 2110/883 = 2.39 days
Oops, I mean... this is the average amount of tonnes removed daily.
It should be the other way round, that is: 0.418 days = 10 hours.
So, if each 10 hours you remove 1 tonne of potatoes, by the end of 8 months, there will be none left.
Either that, or I'm not understanding the problem properly...
EDIT: Or maybe it's simply 273 / 2110 = 0.129 days = 3.1 hours
So, if you remove 1 tonne every hour, by 8 months, there will be none left.