# Math Help - Probability Of Drawing: An ace and two face cards of the same suit.

1. ## Probability Of Drawing: An ace and two face cards all of the same suit.

Ex: Ace of spades, King of Spades, and Queen of spades.

I know there are 4/52 chance of drawing an Ace.
But after i get that ace, i then use the suit of whatever ace i drew, so if it was a spade like in the example i would then find the probability of drawing, without replacement, the face cards that are in the spades category, which would be 3/12(minus one because the ace was drawn and therefore removed a spade) ??

After this i confuse myself, anyone care to put me on the correct path and/or provide me with an answer so that i can figure this out ?

Thanks,
Frank

2. The ace of spades in gone leaving 51 cards, there are 3 face cards that are spades. So the probability becomes 3/51 then for the next two face cards 2/50 and 1/59.

In conclusion $p = \frac{4}{52}\times \frac{3}{51} \times \frac{2}{50}\times \frac{1}{49}$