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Math Help - Probability Of Drawing: An ace and two face cards of the same suit.

  1. #1
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    Probability Of Drawing: An ace and two face cards all of the same suit.

    Ex: Ace of spades, King of Spades, and Queen of spades.

    I know there are 4/52 chance of drawing an Ace.
    But after i get that ace, i then use the suit of whatever ace i drew, so if it was a spade like in the example i would then find the probability of drawing, without replacement, the face cards that are in the spades category, which would be 3/12(minus one because the ace was drawn and therefore removed a spade) ??


    After this i confuse myself, anyone care to put me on the correct path and/or provide me with an answer so that i can figure this out ?

    Thanks,
    Frank
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  2. #2
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    The ace of spades in gone leaving 51 cards, there are 3 face cards that are spades. So the probability becomes 3/51 then for the next two face cards 2/50 and 1/59.

    In conclusion p = \frac{4}{52}\times \frac{3}{51} \times \frac{2}{50}\times \frac{1}{49}
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