Thread: Just checking

I have P(B|A) and P(A), there isn't a quick way to get P(B) off this is there?

A and B are not independent.

Thanks,

Brendan

Hello, Brendan!

I have and

There isn't a quick way to get off this, is there? . no

and are not independent.

From Bayes' Theorem, we have: .

. . Hence: .


But without more information, such as ,

. . we cannot isolate

Thanks, I assumed that was the case but just wanted to be sure.