
residual variance ANOVA
Sunday October 24, 2010:
I am reading a paper on sample size in a clinical study relating to bioequivalence. The values of teh paramater compared are on logarithms and it is a multiplicative model.
We have data from an ANOVA,. The residual variance is (sigma)^2 and
the CV= Squrt [exp^(sigma)1]....this is equation 1
The paper then says The above relationship (equation 1) corresponds to to the relationship *(equation 2)
(sigma)^2 =Ln(1+CV^2).......equation.
Then the paper says : When the square of the CV is small then:
Ln(1+CV^2)= cv^2 holds.
Can this work be explained to me so I can undertstand it better.
Angus