The rest of the two parts are cases of binomial distribution. The probability of his collection earning him the Langkawi trip is 0.323.
X~B(6 , 0.323). Calculate P(X=2) and P(X=6).
You can try substituting positive integers for m=1,2,3,... till it satisfies the condition. In this case, m=4 since P(X=4)=0.026<0.03.
Part(2): In one day, but in n consecutive days, the probability is 0.301^n. Solve for 0.301^n>0.0002 by taking logs.