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Math Help - Discrete Probability Distribution III

  1. #1
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    Discrete Probability Distribution III

    2 more questions... ^^'' I found these two kind of difficult... please teach me to solve them...

    Discrete Probability Distribution III-q14-15.jpg


    Answer:
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  2. #2
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    Quote Originally Posted by cloud5 View Post
    2 more questions... ^^'' I found these two kind of difficult... please teach me to solve them...

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    Answer:
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    (14) X~B(40 , 1/20) implies X~P(2)

    Calculate P(X>=3)

    The rest of the two parts are cases of binomial distribution. The probability of his collection earning him the Langkawi trip is 0.323.
    X~B(6 , 0.323). Calculate P(X=2) and P(X=6).

    (15) X~P(1.2)

    P(X=m)=\frac{e^{-1.2}(1.2)^m}{m!}<0.03

    You can try substituting positive integers for m=1,2,3,... till it satisfies the condition. In this case, m=4 since P(X=4)=0.026<0.03.

    Part(2): In one day, P(X=0)=e^{-1.2}=0.301 but in n consecutive days, the probability is 0.301^n. Solve for 0.301^n>0.0002 by taking logs.
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