2 more questions... ^^'' I found these two kind of difficult... please teach me to solve them...
The rest of the two parts are cases of binomial distribution. The probability of his collection earning him the Langkawi trip is 0.323.
X~B(6 , 0.323). Calculate P(X=2) and P(X=6).
You can try substituting positive integers for m=1,2,3,... till it satisfies the condition. In this case, m=4 since P(X=4)=0.026<0.03.
Part(2): In one day, but in n consecutive days, the probability is 0.301^n. Solve for 0.301^n>0.0002 by taking logs.