Could anyone teach me how to solve these?(Crying)

Attachment 19313

Attachment 19314

Answer:

Q9: (i)0.1108, (ii)0.6227, 2, 0.2681

Q10: (i)0.0803, (ii)0.0498, (iii)0.0032

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- Oct 13th 2010, 03:47 AMcloud5Discrete Probability Distribution II
Could anyone teach me how to solve these?(Crying)

Attachment 19313

Attachment 19314

Answer:

Q9: (i)0.1108, (ii)0.6227, 2, 0.2681

Q10: (i)0.0803, (ii)0.0498, (iii)0.0032 - Oct 13th 2010, 04:07 AMmathaddict
# 9

You are asked to determine the most likely value of X or the mode of this poisson distribution.

$\displaystyle

\frac{P(X=x+1)}{P(X=x)}=\frac{\lambda}{x+1}$ in which lambda is 2.2

Consider for two cases, if P(X=x+1)>P(X=x), then 2.2>x+1, x<1.2 so x=1

P(X=2)>P(X=1)>P(X=0)

If P(X=x+1)<P(X=x), then 2.2<x+1 , x>1.2 so x=2,3,4,...

P(x=2)>P(X=3)>P(X=4)>...

Do you see that P(X=2) has the highest probability? That implies that the value of X most likely to occur is 2. Calculate its probability.

(10) Adjust the mean to get 1/12. - Oct 13th 2010, 06:24 PMcloud5
- Oct 14th 2010, 03:27 AMmathaddict