In 1000 people in a company, the probability of having a disease is 0.005. One of the people is John and he knows he has the disease. What does John think is the probability that more than 1 person including himself has the disease?
I would denote J to be the number of people with the disease excluding john.
The answer is J~Bin(999, p) P(J>0) = 0.993
Can someone explain to me what is happening? How do you have the p?
Hello, sankeel!
In 1000 people in a company, the probability of having a disease is 0.005.
One of the people is John and he knows he has the disease.
What is the probability that more than 1 person including John has the disease?
We have: .
What is the probability that John is the only one infected?
Then the other 999 people are "clean": .
Therefore: .
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