suppose Fy(y)=y^3 for 0<=y<1/2 and Fy(y)=1-y^3 for 1/2<=y<=1. Compute these.

1.

P(1/3<Y<3/4)

2.

P(Y=1/3)

3.

P(Y=1/2)

I am not sure i did the first one right, i did integrals and got the final answer to be

approx. 0.12

Is that what i am supposed to do for this and is 1 right?

for 2. is it

1/27 ?

and 3. is it

1- 1/27 ?