Thread: Seating arrangement

Four married couples are having dinner together. The seating is arranged in such a way that the four ladies draw lots to see which man they end up sitting with.

What is the probability that exactly two wives get to sit with their own husband? The answer is 1/4, but I would like to see a solution involving permutations and/or combinations if possible.

Originally Posted by Mondreus

Four married couples are having dinner together. The seating is arranged in such a way that the four ladies draw lots to see which man they end up sitting with.
What is the probability that exactly two wives get to sit with their own husband? The answer is 1/4, but I would like to see a solution involving permutations and/or combinations if possible.

There are possible ways to seat the women.
There are ways to seat exactly two with their partner.

Shouldn't the husbands be selected in order as well? I understand the basics of permuations and combinations, but I'm having a hard time figuring out how to piece it together.

Originally Posted by Mondreus

Shouldn't the husbands be selected in order as well? I understand the basics of permuations and combinations, but I'm having a hard time figuring out how to piece it together.

No, there is no reason to consider the husbands other than each identifies a position. Think of four two-person tables. Seat the men in any order at each table. Now you have four ‘named’ positions into which we put the women.

The answer says

Originally Posted by Mondreus

The answer says

How does that give as an answer?

I totally disagree with that reasoning.