So it gives me values P(A)=0.5, P(B)=0.5 and P(AnB)=0.3
How do I find P(AnB')???
Note $\displaystyle P(A')=0.5 = P(B')$
And then read this.
Karnaugh maps & probability? - Yahoo! Answers
Hello, calculuskid1!
$\displaystyle \text{Given: }\;P(A)=0.5,\;\;P(B)=0.5,\;\;P(A \cap B)=0.3$
$\displaystyle \text{Find }P(A \cap B')$
Place the given information in a chart . . .
. . $\displaystyle \begin{array}{c||c|c||c|}
& B & B' & \text{Total} \\ \hline \hline
A & 0.3 & & 0.5 \\ \hline
A' & & & \\ \hline \hline
\text{Total} & 0.5 & & 1.0 \\ \hline \end{array}$
And we can fill in the empty cells:
. . $\displaystyle \begin{array}{c||c|c||c|}
& B & B' & \text{Total} \\ \hline \hline
A & 0.3 & 0.2 & 0.5 \\ \hline
A' & 0.2 & 0.3 & 0.5 \\ \hline \hline
\text{Total} & 0.5 & 0.5 & 1.0 \\ \hline \end{array}$
And now we can answer the question.