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Thread: Probability of P(AnB')

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    Probability of P(AnB')

    So it gives me values P(A)=0.5, P(B)=0.5 and P(AnB)=0.3
    How do I find P(AnB')???
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    Try drawing a Karnaugh Map...
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    never heard of a Karnaugh map?
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    Quote Originally Posted by calculuskid1 View Post
    So it gives me values P(A)=0.5, P(B)=0.5 and P(AnB)=0.3
    How do I find P(AnB')???
    Note $\displaystyle P(A')=0.5 = P(B')$

    And then read this.

    Karnaugh maps & probability? - Yahoo! Answers
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  5. #5
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    Hello, calculuskid1!

    $\displaystyle \text{Given: }\;P(A)=0.5,\;\;P(B)=0.5,\;\;P(A \cap B)=0.3$

    $\displaystyle \text{Find }P(A \cap B')$

    Place the given information in a chart . . .

    . . $\displaystyle \begin{array}{c||c|c||c|}
    & B & B' & \text{Total} \\ \hline \hline
    A & 0.3 & & 0.5 \\ \hline
    A' & & & \\ \hline \hline
    \text{Total} & 0.5 & & 1.0 \\ \hline \end{array}$



    And we can fill in the empty cells:

    . . $\displaystyle \begin{array}{c||c|c||c|}
    & B & B' & \text{Total} \\ \hline \hline
    A & 0.3 & 0.2 & 0.5 \\ \hline
    A' & 0.2 & 0.3 & 0.5 \\ \hline \hline
    \text{Total} & 0.5 & 0.5 & 1.0 \\ \hline \end{array}$


    And now we can answer the question.

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