A group of 15-18 year old kids were studied. 68% have a television, 92% have a CD/tape player, and 32% have a computer. Only 4% have none of the above. 9% have a computer and a CD/tape player but no television 44% have a TV and a CD/tape player but no computer, and 1% have a TV and computer but no CD/tape player.
How would I fill out this venn diagram?
Let A= TV, B= CD/tape, C= computer.
(Let u= union and n=intersection)
So, we know that (AnB)= .44, (AnC)= .01, and (BnC)=.09.
We must find (AnBnC).
Total = Group1 + Group2 + Group3 - (sum of 2-group overlaps)+(all three overlap) + Neither.
We get (all three overlap)= -.42. This does not make sense...
I know these formulas but am unsuer how to apply them:
Exactly 2 sets=(sum of 2-group overlaps)-3(all three overlap)
More than 3 sets=(sum of 2-group overlaps)-2(all three overlap).
Am I way off here? What formulas can I use for this?
September 10th 2010, 07:33 PM
This is a tricky one . . .
Construct the Venn diagram and fill in the known quantities.